Saturday, July 13, 2013
Now multiplication of two matrices(matrix) is so easy if use a C program. It is very easy to write and understand. In this we use 2d array. To understand this code you must have a basic knowledge about 2 dimensional array. So, let's try...........
#include<stdio.h>
int main()
{
int a[5][5],b[5][5],c[5][5],i,j,k,sum=0,m,n,o,p;
printf("\nEnter the row and column of first matrix: ");
scanf("%d %d",&m,&n);
printf("\nEnter the row and column of second matrix: ");
scanf("%d %d",&o,&p);
if(n!=o)
{
printf("Matrix mutiplication is not possible: ");
printf("\nColumn of first matrix must be same as row of second matrix: ");
}
else
{
printf("\nEnter the First matrix-> ");
for(i=0;i<m;i++)
for(j=0;j<n;j++)
scanf("%d",&a[i][j]);
printf("\nEnter the Second matrix-> ");
for(i=0;i<o;i++)
for(j=0;j<p;j++)
scanf("%d",&b[i][j]);
printf("\nThe First matrix is\n");
for(i=0;i<m;i++){
printf("\n");
for(j=0;j<n;j++){
printf("%d\t",a[i][j]);
}
}
printf("\nThe Second matrix is\n");
for(i=0;i<o;i++){
printf("\n");
for(j=0;j<p;j++){
printf("%d\t",b[i][j]);
}
}
for(i=0;i<m;i++)
for(j=0;j<p;j++)
c[i][j]=0;
for(i=0;i<m;i++){ //row of first matrix
for(j=0;j<p;j++){ //column of second matrix
sum=0;
for(k=0;k<n;k++)
sum=sum+a[i][k]*b[k][j];
c[i][j]=sum;
}
}
}
printf("\nThe multiplication of two matrix is\n");
for(i=0;i<m;i++){
printf("\n");
for(j=0;j<p;j++){
printf("%d\t",c[i][j]);
}
}
return 0;
}
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