Uva 10370 - Above Average, easy programing problem from Uva

Problem ID - 10370,
Problem Name - Above Average

Problem Description is Here


#include<stdio.h>

main()
{
    int test, n, i, stud[1000];
    float sum, ave, count, percent;
    char ch='%';


    scanf("%d", &test);
    while(test--)
    {
        sum=ave=count=percent=0;
        scanf("%d", &n);
        for(i=0;i<n;i++)
        {
            scanf("%d", &stud[i]);
            sum+=stud[i];
        }

        ave=sum/(float)n;
        for(i=0;i<n;i++)
        {
            if(stud[i]>ave)
            {
                count++;
            }
        }
        percent=(count*100.0)/(float)n;
        printf("%.3f%c\n", percent, ch);
    }
return 0;
}